Question

1 gram of a carbonate of a metal was dissolved in 25 ml of 1N HCl. The resulting liquid required 5 ml of N NaOH for neutralization. The eq. wt. of metal carbonate is__________.

• A. 100
• B. 30
• C. 40
• D. 50

Answer 1

Answer: (D)

50

Equivalents of metal carbonate + equivalents of $HCl$ = Equivalents of $NaOH$

$\frac{1}{W_{eq}}+25\times {10}^{-3}\times 1=5\times {10}^{-3}\times 1$

$\frac{1}{W_{eq}}=20\times {10}^{-3}$

$W_{eq}=50gm/mol$