1+ $i^{2} + i^{4} + i^{6} + . . . . . . . . + i^{2 n}$ is

Positive

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Negative

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Zero

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Cannot be determined

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Solution

The correct option is D Cannot be determined
$1 + i^{2} + i^{4} + . . . . . . . . + i^{2 n}$

$= 1 - 1 + 1 - 1 + 1 - 1......$

Hence it can b positive or negative depending on the value of $2 n$

Hence It cannot be determined from the given data.

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Similar questions

$1 + i^{2} + i^{4} + i^{6} + . . . . . . . . . . + i^{2 n}$ is

$1 + i^{2} + i^{4} + i^{6} + . . . . . i^{2 n}$ is:

1 + i^{2} + i^{4} + i^{6} + . . . . . + i^{2 n}

1 + i^{2} + i^{4} + i^{6} + . . . + i^{2 n}

1 + i^{2} + i^{4} + i^{6} + . . . . . + i^{2 n}

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