If x+y+z=6, xy+xz+yz=11, xyz=6 thenequals
If x,y,z are non negative integers so that x + y + z = 12, then the
maximum value of xyz + xy + yz + zx is
The value of 52xyz(xy+yz+xz+y2)(z+x)×104xy(xy+xz+yz+y2) is: