1 kg ice at −10∘C is mixed with 1 kg of water at 50∘C. When the mixture attains equilibrium, find the mass of ice in final mixture. [Lf=80kcal/kg;Sice=12kcal/kg∘C;Swater=1kcal/kg∘C]
A
4580kg
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B
3580kg
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C
2540kg
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D
3540kg
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Solution
The correct option is B3580kg Mice×Sice×ΔT+mLf=Mwater×ΔT1×12×10+m×80=1×50⇒m=4580or,1−m=3580