$1 k g / m^{3}$ is equal to

10^{3} g / c m^{3}

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1 g / c m^{3}

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10^{- 3} g / c m^{3}

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None of the above

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Solution

The correct option is C $10^{- 3} g / c m^{3}$
$1 k g / m^{3} = 10^{3} g / 10^{6} c m^{3} = 10^{- 3} g / c m^{3}$

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Similar questions

Q. 1

\frac{g}{c m^{3}}

\frac{k g}{m^{3}}

Q. If

1 k g

of water is mixed with

2 k g

of liquid of density

3 g / c m^{3}

, then the average density of mixture will be ?

An object of mass 100 g has a volume of $20 c m^{3}$ . Calculate the density of the object. If the density of water is $1 g / c m^{3}$ . State whether the object will float or sink in water.

Q. Convert

1

g / c m^{3}

k g / m^{3}

Q. The volume occupied by one molecule of water (density

1 g / c m^{3}

) is:

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1 kg/m3 is equal to

The correct option is C 10−3 g/cm31 kg/m3=103g/106cm3=10−3g/cm3

$1 k g / m^{3}$ is equal to

The correct option is C $10^{- 3} g / c m^{3}$
$1 k g / m^{3} = 10^{3} g / 10^{6} c m^{3} = 10^{- 3} g / c m^{3}$