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Question

1 Kg of ice at 20C is mixed with 2 Kg of water at 90C. Assuming that there is no loss of energy to the environment, what will be the final temperature of the mixture? (Assume latent heat of ice =334.4 KJ/Kg, specific heat of water and ice are 4.18 kJ/(kg.K) and 2.09 kJ/(kg.K), respectively.)

A
30C
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B
0C
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C
80C
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D
45C
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Solution

The correct option is A 30C
Heat gained by ice =heat loss by water
1×2.09×20+1×334.4+1×4.18×T=2×4.18×(90T)
T=30o

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