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Byju's Answer

Standard XII

Physics

Work Done on & by the Object

1 kg of iron ...

Question

$1$ kg of iron (specific heat $120$ Cal kg $^{- 1}$ C $^{- 1}$ ) is heated by $1000$ $^{0}$ C. The increase in its mass is :

Zero

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5.6 \times 10

^{- 8}

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5.6 \times 10

^{- 16}

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5.6 \times 10

^{- 12}

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Solution

The correct option is A Zero
Energy given to it $= m S Δ T$
$= (1 k g) (120 \frac{c a l}{K g C}) (1000^{0} C)$
$= 12 \times 10^{4} C a l$
$= 12 \times 10^{4} \times 4.18 J$
$= 50 \times 10^{4} J$

The energy given to it is used to increase its temperature by $1000^{0} C$ , therefore mass increment is ZERO.

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1 kg of iron (specific heat 120 Cal kg−1C−1) is heated by 10000C. The increase in its mass is :

The correct option is A ZeroEnergy given to it =mSΔT =(1kg)(120calKgC)(10000C) =12×104Cal =12×104×4.18J =50×104J The energy given to it is used to increase its temperature by 10000C, therefore mass increment is ZERO.

$1$ kg of iron (specific heat $120$ Cal kg $^{- 1}$ C $^{- 1}$ ) is heated by $1000$ $^{0}$ C. The increase in its mass is :