1 kg of water is supplied 630 kJ of energy- Specific heat of water is 4200 J-kg -C-So calculate the rise in temperature of 1 kg water-

The correct option is D 150^∘C we know that, W=mcθ 630000=1000(4.2) θ θ= 150^oC ...

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Byju's Answer

Standard XII

Physics

Calorimetry

1 kg of water...

Question

1 kg of water is supplied 630 kJ of energy. Specific heat of water is 4200 J/kg $^{\circ} C$ .So calculate the rise in temperature of 1 kg water.

40^{\circ} C

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60^{\circ} C

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80^{\circ} C

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150^{\circ} C

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Solution

The correct option is D $150^{\circ} C$
we know that,
$W = m c θ$
630000=1000(4.2) $θ$
$θ = 150^{o} C$

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1 kg of water is supplied 630 kJ of energy. Specific heat of water is 4200 J/kg ∘C.So calculate the rise in temperature of 1 kg water.

The correct option is D 150∘Cwe know that,W=mcθ630000=1000(4.2)θθ=150oC

1 kg of water is supplied 630 kJ of energy. Specific heat of water is 4200 J/kg $^{\circ} C$ .So calculate the rise in temperature of 1 kg water.

The correct option is D $150^{\circ} C$
we know that,
$W = m c θ$
630000=1000(4.2) $θ$
$θ = 150^{o} C$