$1 l i t$ of oxygen and $3 l i t$ of $S O_{2}$ at $S T P$ are reacted to produce sulphur trioxide. The ration between volume of sulphur trioxide and that of sulphur dioxide after reaction and weight of $S O_{3}$ formed (in grams) respectively are

1 : 2; 7.14 g m s

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2 : 1; 14.28 g m s

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2 : 1; 7.14 g m s

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1 : 1; 14.28 g m s

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Solution

The correct option is A $1 : 2; 7.14 g m s$

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Similar questions

9.02 g

S O_{2}

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Calculate the volume of air at STP, required to convert 300 mL of sulphur dioxide to sulphur trioxide. Air contains 21% oxygen by volume.

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