1 liter of dry air at STP expands adiabatically to a volume of 3 litres. If γ=1.4, the work done by air is (31.4=4.655) (take air to be an ideal gas)
A
48J
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B
90.5J
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C
100.8J
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D
60.7J
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Solution
The correct option is B90.5J Given, P1=1atm, T1=273K (At STP) In adiabatic process, P1Vγ1=P2Vγ2 P2=P1[V1V2]γ P2=1×[13]1.4 P2=0.2164atm Work done in adiabatic process is given by W=P1V1−P2V2γ−1W=1×1−3×.21640.4×101.325 Since, 1atm=101.325kPa and 1Liter=10−3m3 W=89.87J