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Standard XII

Chemistry

Charles' Law

1 litre of a ...

Question

1 litre of a mixture of $C O$ and $C O_{2}$ is taken. This mixture is passed through a tube containing red-hot charcoal. The volume now becomes $1.6$ times. The volumes are measured under the same condition. Find the percentage concentration of $C O$ by volume.

20%

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40%

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30%

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50%

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Solution

The correct option is B 40%
Let volume of $C O_{2}$ be X litre
Volume of $C O$ = 1-X litre
Only $C O_{2}$ will react with charcoal ( C ) to produce $C O$
We assume that all $C O_{2}$ is converted into $C O$
$C O_{2} + C \to 2 C O$
Total volume of CO will be as following
let X $C O_{2}$ converted to 2X $C O$

2X + 1-X =1.6

X=0.6

So,
concentration of $C O_{2}$ is 60% by volume
Hence concentration of $C O$ is 40% by volume

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