Question

1 litre solution containing 490 g of sulphuric acid is diluted to 10 litre with water. What is the normality of the resulting solution?

• A. 0.5 N
• B. 1.0 N
• C. 5.0 N
• D. 10.0 N

Answer 1

Answer: (B)

1.0 N

Equivalent weight of $H_{2}S{O}_4=49$

Given : $490g$ of $H_{2}S{O}_4$ is dissolved in $10L$.

$\therefore$ Mass of solute in $1$ liter $=\frac{490}{10}=49$

$Normality=\frac{Massofsoluteing/d{m}^3}{Equivalentweight}=\frac{49}{49}=1.0N$