1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# 1 M HCl and 2 M HCl are mixed in volume ratio of 4:1. The resulting HCl solution is diluted to double its original volume. What is the final molarity of HCl solution?

A
0.75 M
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
B
1.2 M
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
C
0.6 M
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.5 M
No worries! Weâ€˜ve got your back. Try BYJUâ€˜S free classes today!
Open in App
Solution

## The correct option is C 0.6 MLet volume of 1 M HCl solution is 4V Litres and 2 M HCl solution is V Litres. Then, molarity after mixing can be given as, M′=M1×V1+M2×V2V′ where, M′ and V′ are molarity and volume of solution mixture, V1 and V2 are 4V and V respectively. So, M′=1×4V+2×V4V+V=1.2 M Now, final volume is doubled after dilution, So final volume(Vf)=2V′=10V ∴ Mf=M′×V′Vf=0.6M

Suggest Corrections
14
Join BYJU'S Learning Program
Explore more
Join BYJU'S Learning Program