Question

1 M solution of $H_{2}S{O}_4$ is diluted from $1$ litres to $5$ litres, the normality of the resulting solution will be:

• A. $0.2N$
• B. $0.1N$
• C. $0.4N$
• D. $0.5N$

Answer 1

The correct option is C $0.4N$

$Weightofthe{H}_{2}S{O}_4=Molarity\times mol.wt\times volumeinlitrewt.ofthe{H}_{2}S{O}_4=1\times 98\times 1=98$

equivalent weight of $H_{2}S{O}_4=\frac{molecularweight}{basicity}=\frac{98}{2}=48$

Normality of resulting solution

$=\frac{wt}{eq.wt}\times \frac{1}{volumeinlit.}=\frac{98}{49}\times \frac{1}{5}=0.4N$

So the resulting solution normality is $0.4N$.