Question

$1$ ml of $H_2{O}_2$ solution gives $10$ml of $O_2$ at N.T.P. It is:

• A. $10$ vol $H_2{O}_2$
• B. $20$ vol $H_2{O}_2$
• C. $30$ vol $H_2{O}_2$
• D. $40$ vol $H_2{O}_2$

Answer 1

Answer: (A)

$10$ vol $H_2{O}_2$

$2H_2{O}_2⟶2H_{2}O+O_2\uparrow$

Volume of $O_2$ gas at N.T.P. obtained by decomposition of unit volume solution of $H_2{O}_2$ is known as volume strength of $H_2{O}_2$ solution.

Therefore, 1 ml of $H_2{O}_2⟶$10 ml of $O_2$

So, volume strength of $H_2{O}_2$ is 10 volume or 10 V.