1 ml of H 2 O 2 solution gives 10 ml of O 2 at N-T-P- It isA- 10 V ol H 2 O 2B- 20 V ol H 2 O 2C- 30 V ol H 2 O 2D- 40 V ol H 2 O 2

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Standard XII

Chemistry

System, Surroundings, Intensive, Extensive Properties

1 ml of H 2 O...

Question

1 ml of $H_{2} O_{2}$ solution gives 10 ml of $O_{2}$ at N.T.P, It is

10 V o l H_{2} O_{2}

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20 V o l H_{2} O_{2}

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30 V o l H_{2} O_{2}

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40 V o l H_{2} O_{2}

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Solution

The correct option is A $10 V o l H_{2} O_{2}$
1 ml of $H_{2} O_{2}$ give 10 ml of $O_{2}$
1 lit of $H_{2} O_{2}$ give 10 lit of $O_{2}$

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Arrange the following compounds in increasing order of boiling point. Propan - 1 - ol, butan - 1 - ol, butan - 2 - ol, pentan - 1 - ol
(a) Propan-1-ol, butan-2-ol, butan - 1 - ol, pentan-1-o|
(b) Propan-1-ol, butan - 1 - ol, butan-2-ol, pentan-1-ol
(c) Propan-1-ol, butan-2-ol, butan-1-ol, pentan-1-ol
(d) Propan-1-ol, butan-1-ol, butan-2-ol, pentan-1-ol

Equation $H_{2} S + H_{2} O_{2} \to S + 2 H_{2} O$ represents

The reaction H₂S + H₂O₂ → SO₂+ 2H₂O manifests

The reaction $H_{2} S + H_{2} O_{2} ⟶ 2 H_{2} O + S$ shows

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1 ml of H2O2 solution gives 10 ml of O2 at N.T.P, It is

The correct option is A 10Vol H2O21 ml of H2O2 give 10 ml of O2 1 lit of H2O2 give 10 lit of O2

1 ml of $H_{2} O_{2}$ solution gives 10 ml of $O_{2}$ at N.T.P, It is

The correct option is A $10 V o l H_{2} O_{2}$
1 ml of $H_{2} O_{2}$ give 10 ml of $O_{2}$
1 lit of $H_{2} O_{2}$ give 10 lit of $O_{2}$