1 mol of CH 4 containsA- 4 g atom of HydrogenB- 3-0 g of carbonC- 1-81 - 1023 molecules of CH 4D- 6-02 - 1023 atoms of H

1 mol of CH 4...

Question

1 mol of $C H_{4}$ contains

$6.02 \times 10^{23}$ atoms of H

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4 g atom of Hydrogen

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$1.81 \times 10^{23}$ molecules of $C H_{4}$

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3.0 g of carbon

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Solution

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0.1

C H_{4} + 3.01 \times 10^{23}

C H_{4} - 9.6

C H_{4} = x

H

x

6.02 \times 10^{23}

6.02 \times 10^{23}

P_{4}

C O_{2}

6.02 \times 10^{23}

3.01 \times 10^{23}

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