1 mol of MnO2-4 in neutral aqueous medium disproportionates to -

The correct option is A 2/3 mol of MnO^⊝_4 and 1/3 mol of MnO_2 In neutral medium, K_2MnO_4 (potassium mangnanate) disproportionat ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Compressibility Factor

1 mol of Mn...

Question

$1$ mol of $M n O_{4}^{2 -}$ in neutral aqueous medium disproportionates to :

\frac{2}{3}

mol of

M n O_{4}^{⊝}

and

\frac{1}{3}

mol of

M n O_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{3}

mol of

M n O_{4}^{⊝}

and

\frac{2}{3}

mol of

M n O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3}

mol of

M n_{2} O_{7}

and

\frac{2}{3}

mol of

M n O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{3}

mol of

M n_{2} O_{7}

and

\frac{1}{3}

mol of

M n O_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{2}{3}$ mol of $M n O_{4}^{⊝}$ and $\frac{1}{3}$ mol of $M n O_{2}$
In neutral medium, $K_{2} M n O_{4}$ (potassium mangnanate) disproportionate as follows:
$K_{2} M n O_{4} \to K M n O_{4} + M n O_{2}$
On balancing, we get
$3 M n O_{4}^{2 -} + 2 H_{2} O \to 2 M n O_{4}^{⊝} + 4 ⊝ O H + M n O_{2}$
$1$ mol $M n O_{4}^{2 -} \equiv \frac{2}{3}$ mol $M n O_{4}^{⊝} = \frac{1}{3}$ mol $M n O_{2}$

Suggest Corrections

Similar questions

K M n O_{4}

acts as an oxidising agent in the neutral medium and gets reduced to

M n O_{2}

.The equivalent weight of

K M n O_{4}

in neutral medium

Q. 1 mol of

K C l O_{3}

is heated in the presence of

M n O_{2}

. The produced oxygen is used to react with aluminium. Find the number of moles of aluminium oxide formed.

How much charge is required for the following reductions:

(i) 1 mol of Al³⁺ to Al.

(ii) 1 mol of Cu²⁺to Cu.

(iii) 1 mol of to Mn²⁺.

Q. An aqueous solution of borax that has

1 mol

of borax reacts with

2 mol

of acids. This is because of the formation of:

Q. If NaCl is doped with

10^{- 3} m o l

S r C l_{2}

, then the concentration of cation vacancies will be

Join BYJU'S Learning Program

1 mol of MnO2−4 in neutral aqueous medium disproportionates to :

The correct option is A 23 mol of MnO⊝4 and 13 mol of MnO2In neutral medium, K2MnO4 (potassium mangnanate) disproportionate as follows:K2MnO4→KMnO4+MnO2On balancing, we get3MnO2−4+2H2O→2MnO⊝4+4⊝OH+MnO21 mol MnO2−4≡23 mol MnO⊝4=13 mol MnO2

$1$ mol of $M n O_{4}^{2 -}$ in neutral aqueous medium disproportionates to :