1 molal aqueous solution of an electrolyte A2B3 is 60% ionised . The boiling point of the solution at 1 atm in K is ( Rounded -off to the nearest integer ) [Kbfor(H2O)=0.53KKgmol−1]
(JEE MAIN 2021)
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Solution
( Assuming A - cation , B - anion ) A2B3→2A3++3B2−1−0.62×0.63×0.6∴van't Hoff factor =1−0.6+1.2+1.8=3.4ΔTb=i×Kb×mΔTb=3.4×0.52×1=1.768Tb−373=1.768Tb=374.77≈375(Nearest integer)