$1$ mole aqueous solution of $S O_{2} C l_{2}$ is neutralised by ........... moles of $K O H$ .

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Solution

$S O_{2} C l_{2} 1 m o l + 2 H_{2} O ⟶ H_{2} S O_{4} 1 m o l + 2 H C l 2 m o l$

$1 m o l H_{2} S O_{4} \equiv 1 m o l C a (O H)_{2} = 2 m o l K O H$
$\frac{1}{2} m o l C a (O H)_{2} \equiv 1 m o l K O H$
$2 m o l H C l \equiv 1 m o l C a (O H)_{2} \equiv 2 m o l K O H$

Thus, a mixture of $1 m o l H_{2} S O_{4}$ and $2 m o l H C l$ requires $4 m o l K O H$ .

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