Question

$1$-mole atom of diatomic gas at NTP will be $11.2\mathrm{L}$ liters.

Answer 1

Step 1: Given data

The volume of $1$-mole atom of diatomic gas at NTP = $11.2\mathrm{liters}$.

A diatomic gas is a gas consisting of two atoms.

The NTP(Normal Temperature and Pressure conditions) conditions are:

$\mathrm{Temperature}=293.15\mathrm{K}$

$\mathrm{Pressure}=1\mathrm{atm}$

Step 2: Calculation of the volume of 1 mole of a diatomic gas.

$1$ mole of a diatomic gas occupies$22.4\mathrm{L}$ at NTP.

No. of atoms in a diatomic gas = $2$

Volume occupied by $2$ moles of atoms of diatomic gas = $22.4\mathrm{L}$

The volume occupied by $1$ mole of an atom of diatomic gas = $\frac{22.4L}{2}=11.2L$

Hence, $1$-mole atom of diatomic gas at NTP will be $11.2\mathrm{L}$ liters.