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Question

1-mole atom of diatomic gas at NTP will be 11.2L liters.


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Solution

Step 1: Given data

The volume of 1-mole atom of diatomic gas at NTP = 11.2liters.

A diatomic gas is a gas consisting of two atoms.

The NTP(Normal Temperature and Pressure conditions) conditions are:

Temperature=293.15K

Pressure=1atm

Step 2: Calculation of the volume of 1 mole of a diatomic gas.

1 mole of a diatomic gas occupies22.4L at NTP.

No. of atoms in a diatomic gas = 2

Volume occupied by 2 moles of atoms of diatomic gas = 22.4L

The volume occupied by 1 mole of an atom of diatomic gas = 22.4L2=11.2L

Hence, 1-mole atom of diatomic gas at NTP will be 11.2L liters.


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