Question

# $1$-mole atom of diatomic gas at NTP will be $11.2\mathrm{L}$ liters.

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Solution

## Step 1: Given data The volume of $1$-mole atom of diatomic gas at NTP = $11.2\mathrm{liters}$.A diatomic gas is a gas consisting of two atoms. The NTP(Normal Temperature and Pressure conditions) conditions are: $\mathrm{Temperature}=293.15\mathrm{K}$$\mathrm{Pressure}=1\mathrm{atm}$Step 2: Calculation of the volume of 1 mole of a diatomic gas. $1$ mole of a diatomic gas occupies$22.4\mathrm{L}$ at NTP.No. of atoms in a diatomic gas = $2$Volume occupied by $2$ moles of atoms of diatomic gas = $22.4\mathrm{L}$The volume occupied by $1$ mole of an atom of diatomic gas = $\frac{22.4L}{2}=11.2L$Hence, $1$-mole atom of diatomic gas at NTP will be $11.2\mathrm{L}$ liters.

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