1 mole of a gaseous aliphatic compound CnH3m is completely burnt in an excess of oxygen. The moles of H2O formed are:
A
mmol
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B
3m2mol
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C
2mol
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D
3mmol
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Solution
The correct option is B3m2mol CnH3m+O2→CO2+3m2H2O Since all the H goes in H2O we do not need to balance oxygen and carbon atoms, we can directly calculate. 1 mol of CnH3m produces 3m2 mol of hydrogen gas.