Question

$1$ mole of Al is deposited by X coulomb of electricity passing through aluminium nitrate solution. Calculate the number of moles of silver deposited by X coulomb of electricity from silver nitrate solution.

• A. $3$
• B. $4$
• C. $2$
• D. $1$

Answer 1

Answer: (A)

$3$

The electrolysis of $Al$ is given by-

$A{l}^{3+}+3e^{-}\to Al$

So, 1 mole of $Al$ is liberated by $3F$ of electricity.

Now electrolysis of $Ag$ is given by,

$A{g}^{+}+e^{-}\to Ag$

So, $1F$ is required to liberate 1 mole of $Ag$.

3 moles is required to liberate $1\times 3$ moles of $Ag$

Hence, 3 moles of $Ag$ is liberated from silver nitrate.

Therefore, option A is correct.