1 mole of an ideal gas is allowed to expand isothermally at 27oC until its volume is tripled. Calculate ΔSsys and ΔSuniv under the following conditions: (a) the expansion is carried out reversibly. (b) the expansion is a free expansion
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Solution
(a) ΔSsys=9.135JK−1mol−1 ΔSsurr=−9.135JK−1mol−1 ΔSuniv=0 (b) ΔSuniv=ΔSsys=9.135JK−1mol−1 (a) In isothermal reversible process ΔS=qrevT q=−W=2.303RTlogV2V1 =2740.6kJmol−1 ΔSsys=qrevT=9.135JK−1mol−1 (b) In the case of free expansion ΔS=2.303nRlogV2V1