1 mole of an ideal gas is subjected to a reversible process as shown in the figure. Calculate the work done (in joule) in this process. [ln 2 = 0.7]
A
0.5 Joule
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B
6 Joule
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C
8 Joule
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D
0.8 Joule
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Solution
The correct option is A 0.5 Joule The given graph is of pressure against reciprocal of volume. From this, the volume at points A and B is calculated as 1 m3 and 0.67 m3 respectively. A graph of pressure versus volume is plotted. The work done is given by the area ABCDE. Work done = area ABCDE = area of triangle ABC + area of rectangle ACDE =12×(0.33m3×1pascal)+(0.33m3×1pascal)=0.5pascalm3=0.5J Hence, the work done is 0.5J.