Question

1 mole of an ideal gas is subjected to a reversible process as shown in the figure.

Calculate the work done (in joule) in the process.

$[ln2=0.7]$(Pressure is in pascal and volume is in $m^{-3}$)

• A. 0.6 Joule
• B. 6 Joule
• C. 8 Joule
• D. 0.8 Joule

Answer 1

The correct option is A 0.6 Joule

From the given graph,

$P=m\times \frac{1}{V}+C$

$1=m\times 1+C$

$1.5=m\times 2+C$

$m=0.5,C=0.5$

$P=\frac{1}{2V}+\frac{1}{2}$

Work done $=-\int PdV=-{\int }_1^{0.5}\frac{1}{2}(\frac{1}{V}+1)dV=0.6Joule$