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Standard XII

Chemistry

Internal Energy

1 mole of an ...

Question

1 mole of an ideal gas with $γ = 1.4$ is adiabatically compressed so that its temperature rises from $27^{o} C$ to $35^{o} C$ . The change in internal energy of the gas is (R $=$ 8.3 Joule mole $^{- 1} K^{- 1}$ )

-166J

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+ 166J

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-168 J

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+ 168

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Solution

The correct option is B + 166J
The change in internal energy is given by,
$U = \frac{n R Δ T}{γ - 1}$
$U = \frac{1 \times 8.314 (35 - 27)}{1.4 - 1}$
Thus, U = 166 J

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One mole of an ideal gas $(γ = 1.4)$ is adiabatically compressed so that its temperature rises from $27^{o} C t o 35^{o} C$ . The change in the internal energy of the gas is (given R = 80. J / mole / K)

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1 mole of an ideal gas with γ=1.4 is adiabatically compressed so that its temperature rises from 27oC to 35oC. The change in internal energy of the gas is (R= 8.3 Joule mole−1K−1)

The correct option is B + 166JThe change in internal energy is given by,U=nRΔTγ−1U=1×8.314(35−27)1.4−1Thus, U = 166 J

1 mole of an ideal gas with $γ = 1.4$ is adiabatically compressed so that its temperature rises from $27^{o} C$ to $35^{o} C$ . The change in internal energy of the gas is (R $=$ 8.3 Joule mole $^{- 1} K^{- 1}$ )

The correct option is B + 166J
The change in internal energy is given by,
$U = \frac{n R Δ T}{γ - 1}$
$U = \frac{1 \times 8.314 (35 - 27)}{1.4 - 1}$
Thus, U = 166 J