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Question

1 mole of an ideal non-linear triatomic gas is adiabatically expanded from 16 atm, 300K to 1 atm. Calculate q,W,ΔU,ΔH if process is carried out reversibly.

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Solution

Since the process is adiabatic no heat is exchanged between system and surroundings so q=0
ΔU=q+W (eq 1)
W=2.303nRTlnP1P2
Given P1=16 atm
P2=1 atm
T=300 K
n=1
W=2.303×1×8.314×300ln161=16084 J=16.084kJ
ΔU=16.084 kJ (From eq 1)

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