1 mole of Ba OH 2 will exactly neutralizeA- 0-5 mole HClB- 1 mole of H 2 SO 4C- 1 mole of H 3 P O 3D- 2 moles of H 3 P O 2

The correct options are B 1 mole of H_2SO_4 C 1 mole of H_3PO_3 D 2 moles of H_3PO_2Ba(OH)_2 → diacidic 1 × 2 = equivalents H_2SO_4 → dibasic 1 × 2 = 2 ...

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Byju's Answer

Standard XII

Chemistry

Other Compounds of Phosphorus

1 mole of Ba ...

Question

1 mole of $B a (O H)_{2}$ will exactly neutralize

0.5 mole HCl

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1 mole of

H_{2} S O_{4}

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1 mole of

H_{3} P O_{3}

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2 moles of

H_{3} P O_{2}

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Solution

The correct options are
B 1 mole of $H_{2} S O_{4}$
C 1 mole of $H_{3} P O_{3}$
D 2 moles of $H_{3} P O_{2}$
$B a (O H)_{2} \to d i a c i d i c$
$1 \times 2 = e q u i v a l e n t s$
$H_{2} S O_{4} \to d i b a s i c 1 \times 2 = 2 e q u i v a l e n t s$
$H_{3} P O_{4} \to d i b a s i c 1 \times 2 = 2 e q u i v a l e n t s$
$H_{3} P O_{2} \to m o n o b a s i c 2 \times 1 = 2 e q u i v a l e n t s$

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1 mole of Ba(OH)2 will exactly neutralize

The correct options are B 1 mole of H2SO4 C 1 mole of H3PO3 D 2 moles of H3PO2Ba(OH)2→diacidic 1×2=equivalents H2SO4→dibasic 1×2=2 equivalents H3PO4→dibasic 1×2=2 equivalents H3PO2→monobasic 2×1=2 equivalents

1 mole of $B a (O H)_{2}$ will exactly neutralize