Question

1 mole of chlorine combines with certain wt. Of a metal giving 111g of its chloride . The same amt. Of metal can displace 2g of hydrogen from an acid. At. Wt. Of metal?

Answer 1

Dear Student,

The metal compound is not given, hence by considering metal as "X" the computation are proceeded as below,

$$\begin{gathered} C{l}_2+X\to n^{*}XCl \\ wherenismoles \end{gathered}$$

from the questionnaire it is known that 1 mole of chlorine contains 71 gm of chlorine leads to 111 gm of the metal chloride.

also given that metal displaces 2 gm of hydrogen element (H) results in 2+ charge formation,

based on the charge the metal compound can be assumed to be Ca, Mg etc.., and based on moles it will be Na, K etc..,

as chlorine gives 1- charge it has to be multiplied with 2 molecules to achieve 2- charge hence the compound formation can be assumed as XCl_​2 ( based on charge) and 2XCl (based on moles)

The simple algebraic computaion for the determination of the weight of the chloride is represented below,

Wt.of chloride = 111= 2(35.5) + x

x = 40

based of 40 molar mass the element of metal is only of Calcium.

Hence our metal component for the given questionnaire is Calcium.

Regards.