1 mole of co-ordinate compound $C o C l_{3}$ on reaction with excess AgNCl $143.5$ gms of AgCl ppt . Then number of chloride ions satisfying both primary valency and secondary valency are?

2

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Solution

The correct option is A $2$
Moles of $A g C l$ formed $= \frac{143.5}{143.5} = 1$
$1$ mole of $C o C l_{3}$ gives $1$ mol of $A g C l$ ppt.
Secondary valence is the number of ions that are coordinated to metal ion. Here, $1 C l^{-}$ ion is not coordinated to the metal ion, due to which it gives $A g C l$ ppt. Hence, no. of chloride ions satisfying the given condition $= 2.$

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Similar questions

1 mole of amino cobalt chloride on treating with an excess of $A g N O$ $_{3}$ solution gives $2$ moles of $A g C l$ precipitate. The number of $C l^{-}$ ions which satisfies both primary and secondary valency of cobalt in the complex is:

Q. In the complex

C o C l_{3} \cdot 5 N H_{3}

one

C l^{-}

ion satisfies primary and secondary valencies of cobalt(III)
If true 1 else 0.

Q. Assertion :Aqueous solution of the compound

C o C l_{3} .4 N H_{3}

when treated with excess of

A g N O_{3}

, 1 mole of

A g C l

is precipitated. Reason: The compound

C o C l_{3} .4 N H_{3}

has six primary valencies and one secondary valency.

In the complex

C o C l_{3} \cdot 5 N H_{3}

, one

C l^{-}

ion satisfies primary and secondary valencies of cobalt(III).

Number of $C l^{-}$ ions satisifying both primary and secondary valency are in $C o C l_{3} .5 N H_{3}$ .

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1 mole of co-ordinate compound CoCl3 on reaction with excess AgNCl 143.5gms of AgCl ppt . Then number of chloride ions satisfying both primary valency and secondary valency are?

1 mole of co-ordinate compound $C o C l_{3}$ on reaction with excess AgNCl $143.5$ gms of AgCl ppt . Then number of chloride ions satisfying both primary valency and secondary valency are?