1 mole of equimolar mixture of Fe2(C2O4)3 and FeC2O4 requires X moles of KMnO4 in acidic medium for complete oxidation. The value of X is:
A
0.6
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B
0.9
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C
1.2
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D
0.8
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Solution
The correct option is B 0.9 KMnO4will oxidiseFe+2 to Fe+3 to CO2. (3C3+2→6C4−+6e−) (C3+2→2C4−+2e−) Fe2+→Fe3++e− Equation of KMnO4 = equation ofFeC2O4 + equation ofFe2(C2O4)3 0.5×6+0.5×3=X×(5) X=0.9moles