1 mole of methyl amine on reaction with nitrous acid forms how many volume of nitrogen?

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Solution

Methylamine on reaction with nitrous acid forms Nitrogen Gas.
$C H_{4} N H_{2} + H N O_{2} ⟶ C H_{3} O H + H_{2} O + N_{2} ↑$
Where, $C H_{4} N H_{2}$ is Methylamine and $H N O_{2}$ is Nitrous acid and $N_{2}$ is Nitrogen Gas.
Herew, one mole of $C H_{2} N H_{2}$ is reacted. So, $1$ $m o l e$ of $N_{2}$ is formed.
Volume of one mole of $N_{2} = 22.4$ $L i t r e s$ .

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