Question

$1mole$ of monatomic ideal gas undergoes a cyclic process shown in the $PV$ diagram. The process $BC$ is isothermal and the temperature at $B$ is $800K$. Find the work done by the gas during the process $ABC$.

Answer 1

$B⟶C$

Workdone,

$W_1=nRT\ln \frac{V_2}{V_1}=1.R.800.\ln \frac{{2V}_0}{V_0}=800\times 8.32\ln 2=6656\ln 2$

$C⟶A$

Workdone,

$W_2=Pdv$

$=P_0(V_0-{2V}_0)=-P_0{V}_0$

$A⟶B$

Isochoric process,

$\therefore$$W_3=0$

$\therefore$ Total work done,

$W=W_1+W_2+W_3$

$=6656\ln 2-P_0{V}_0$.