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Chemical Reactivity

1 mole of N...

Question

1 mole of $N H_{2} O H$ reacts with 2 moles of Ti(III) in the presence of excess alkali and the Ti(III) is converted into Ti(IV).
If true enter 1, else enter 0.

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Solution

The reaction of $N H_{2} O H$ with Ti(III) in the presence of excess alkali is as follows:
$2 T i^{3 +} + N H_{2} O H + H_{2} O ⟶ 2 T i^{4 +} + N H_{3} + 2 O H^{-}$
Ti(III) changes to Ti(IV) and $N H_{2} O H$ is reduced to $N H_{3}$ .
Hence, the correct option is 1.

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