Relation between P, V, T, Gamma in Adiabatic Proceses
1 mole of N H...
Question
1 mole of NH3 gas at 27oC is expanded in reversible adiabatic condition to make volume 8 times (γ=1.33). Final temperature and magnitude of work done respectively are
A
150 K, 900 cal
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B
150 K, 400 cal
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C
250 K, 1000 cal
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D
200 K, 800 cal
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Solution
The correct option is A 150 K, 900 cal For a reversible adiabatic process : T1Vγ−11=T2Vγ−12 Given, T1=300K V2=8V1 putting the values we get, ⇒300×V1/31=T2(8V1)1/3T2=150K So, final temperature is 150K
and work done will be , W=nCv(T2−T1) we know Cv=Rγ−1 so, W=1×Rγ−1(150−300)=21.33−1(−150)=−900cal