You visited us 1 times! Enjoying our articles? Unlock Full Access!

Real Gas Equation

1 mole of S...

Question

1 mole of $S O_{2}$ occupies a volume of $350 m l$ at $300 K$ and $50 a t m$ pressure. Calculate the compressibility factor of the gas.

0.888

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.711

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.520

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.987

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $0.711$
Given $P = 50 a t m, V = 350 m l = 0.350 l i t r e, n = 1 m o l e$ and $T = 300 K$
Now, Compressibility factor $Z = \frac{P V}{n R T}$
$∴ Z = \frac{50 \times 0.350}{1 \times 0.082 \times 300} = 0.711$

Suggest Corrections

Similar questions

Q. Calculate the compressibility factor for

S O_{2}

, if

1 m o l e

of it occupies

0.35 l i t r e

300 K

and

50 a t m

pressure. Comment on the result.

Q. Calculate the compressibility factor for a gas, if

1

mole of it occupy

0.821 litre

300 K

and

50 atm

A mole of $C C l_{4}$ vapours at $77^{\circ} C$ occupies a volume of 36.0 L.If vanderwaals constants are $a = 20.39 L^{2} a t m m o l^{- 2}$ and $b = 0.1383 L m o l^{- 1}$ calculate the compressibility factor Z under (a) low pressure region and (b) high pressure region.
The values of compressibility factor Za and Zb respectively are:

Q. A real gas obeys

P (V - b) = n R T

. 1 mole of this gas at

S T P

occupies 25

L

volume. Calculate compressibility factor :(as nearest integer)

Q. Calculate the volume occupied by

4

mole of an ideal gas at

2.5 \times 10^{5} N m^{- 2}

pressure and

300 K

temperature.

Join BYJU'S Learning Program

1 mole of SO2 occupies a volume of 350ml at 300K and 50atm pressure. Calculate the compressibility factor of the gas.

The correct option is C 0.711Given P=50 atm, V=350ml=0.350 litre, n=1 mole and T=300KNow, Compressibility factor Z=PVnRT∴ Z=50×0.3501×0.082×300=0.711

1 mole of $S O_{2}$ occupies a volume of $350 m l$ at $300 K$ and $50 a t m$ pressure. Calculate the compressibility factor of the gas.

The correct option is C $0.711$
Given $P = 50 a t m, V = 350 m l = 0.350 l i t r e, n = 1 m o l e$ and $T = 300 K$
Now, Compressibility factor $Z = \frac{P V}{n R T}$
$∴ Z = \frac{50 \times 0.350}{1 \times 0.082 \times 300} = 0.711$