$1 m o l e$ of stachyose on hydrolysis yields:

1 m o l e

of glucose +

1 m o l e

of fructose +

2 m o l e

of galactose

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 m o l e

of glucose +

1 m o l e

of fructose +

1 m o l e

of galactose

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 m o l e

of glucose +

2 m o l e

of fructose +

1 m o l e

of galactose

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 m o l e

of glucose +

2 m o l e

of fructose

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $1 m o l e$ of glucose + $1 m o l e$ of fructose + $2 m o l e$ of galactose
Stachyose is a tetrasaccharide consisting of two $α - D$ Galactose units, one $α - D$ glucose unit and a $β - D$ fructose unit. Hence upon hydrolysis of one mole of stachyose, the constituents will separate out resulting into $1 m o l e$ of glucose, $1 m o l e$ of fructose and $2 m o l e s$ of galactose

Suggest Corrections

Similar questions

Choose the correct combinations of the monosaccharides forming disaccharides.

i. Glucose + Glucose = Maltose ii. Glucose + Fructose = Lactose

iii. Glucose + Fructose = Sucrose iv. Glucose + Galactose = Lactose

Choose the correct combinations of the monosaccharides forming disaccharides.
i. Glucose + Glucose = Maltose ii. Glucose + Fructose = Lactose

iii. Glucose + Fructose = Sucrose iv. Glucose + Galactose = Lactose

A) Sucrose	i) Glucose $+$ Fructose $+$ Galactose
B) Lactose	ii) Glucose $+$ Fructose
C) Maltose	iii) Glucose $+$ Galactose
D) Raffinose	iv) Glucose $+$ Glucose