1μC charge is uniformly distributed on a spherical shell given by equation x2+y2+z2=25. The intensity of electric field at a point P(1,1,2)m is .
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Solution
Given:
Equation of spherical shell,x2+y2+z2=25 ⇒x2+y2+z2=52
On comparing it with equation of sphere,x2+y2+z2=r2, we get radius, r=5m.
Also,OP=√(x2−x1)2(y2−y1)2+(z2−z1) OP=√(1−0)2(1−0)2+(2−0) OP=√6=2.45m<5 m
Therefore point P lies inside the spherical shell.
We know that for any uniformly charged spherical shell, electric field at any point inside the shell is zero.