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Question

1) Na2O2Water−−−0 oCP+Q

2) Na2O2Water−−−25 oCP+R+S
Calculate the sum of bond orders between same bonded atoms in Q and R compounds.

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Solution

1) Na2O2Water−−−0 oCNaOH(P)+H2O2(Q)

2) Na2O2Water−−−25 oCNaOH(P)+O2(R)+H2O(S)

Bond order of [OO] in H2O2=1
Bond order of [OO] in O2=2
So, sum=3

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