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Byju's Answer
Standard VIII
Physics
CGS, FPS and MKS System
1 Newton =
Question
1 Newton
=
A
10
4
d
y
n
e
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B
10
5
d
y
n
e
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C
10
6
d
y
n
e
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D
10
7
d
y
n
e
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Solution
The correct option is
B
10
5
d
y
n
e
S.I. unit of force is Newton and CGS unit of force is done.
We know
F
=
m
a
so, force can be expresses in S.I. Units as
K
g
m
s
−
2
and dyne can be expressed as
g
c
m
s
−
2
1 Newton=
k
g
m
s
−
2
=
10
3
g
∗
10
2
c
m
s
s
−
2
=
10
5
g
c
m
s
−
2
=
10
5
d
y
n
e
Suggest Corrections
2
Similar questions
Q.
When a force is expressed in dyne, the number of significant figures is four. If it is expressed in newton, the number of significant figures will become:
(Given:
10
5
d
y
n
e
=
1
N
)
Q.
Using dimensions, show that
1
n
e
w
t
o
n
=
10
5
d
y
n
e
Q.
1 newton metre = 1
___
.
Q.
At a pressure of
24
×
10
5
d
y
n
e
/
c
m
2
, the volume of
O
2
is 10 litre and mass is 20g. The r.m.s velocity will be-
Q.
1 newton = _________ dyne.
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