Question

$1\%$ of ${10}^{12}$ Hz of a satellite link was used for TV station. The number of channels or subscribers, if each channel is of $8kHz$ are

• A. $2.5\times {10}^7$
• B. $1.25\times {10}^6$
• C. $2.5\times {10}^8$
• D. $1.25\times {10}^8$

Answer 1

Answer: (B)

$1.25\times {10}^6$

$1\%$ of ${10}^{12}={10}^{10}Hz$
Number of channels $=\frac{{10}^{10}}{8\times {10}^3}=1.25\times {10}^6$