1- - -2 are the cube roots of unity then the roots of x-13-8-0A- 1-1-2 - 1-2 -2B- 2-2- 2-2C- -2-2-2-2D- -11-2 - 1-2 -2

The correct option is D x 1 = 2, 2ω, 2ω^2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Cube Root of a Complex Number

1, ω, ω2 are ...

Question

1, $ω$ , $ω^{2}$ are the cube roots of unity then the roots of $(x - 1)^{3} + 8 = 0$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

1, ω, ω^{2}

\frac{1}{1 + 2 ω} - \frac{1}{1 + ω} + \frac{1}{2 + ω} =

1, ω, ω^{2}

(x - 3)^{2} + 8 = 0

ω

\frac{1 + 2 ω + 3 ω^{2}}{2 + 3 ω + ω^{2}} + \frac{2 + 3 ω + ω^{2}}{3 + ω + 2 ω^{2}} =

1, ω, ω^{2}

\frac{1}{2 + ω} + \frac{1}{1 + 2 ω} = 1 + ω^{2}

ω (\neq 1)

\frac{1}{a + ω} + \frac{1}{b + ω} + \frac{1}{c + ω} = 2 ω^{2} a n d \frac{1}{a + ω^{2}} + \frac{1}{b + ω^{2}} + \frac{1}{c + ω^{2}} = 2 ω

\frac{1}{a + 1} + \frac{1}{b + 1} + \frac{1}{c + 1}

Join BYJU'S Learning Program