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Linear Combination of Atomic Orbitals

1 On the bas...

Question

$1)$ On the basis of the following observation made with aqueous solutions, assign secondary valences to metal in the following compounds:

$\begin{matrix} Formula & Moles of A g C l precipitated per mole of the compounds with excess A g N O_{3} P d C l_{2} .4 N H_{3} & 2 \end{matrix}$

$2)$ On the basis of the following observation made with aqueous solutions, assign secondary valences to metal in the following compounds:

$\begin{matrix} Formula & Moles of A g C l precipitated per mole of the compounds with excess A g N O_{3} N i C l_{2} .6 H_{2} O & 2 \end{matrix}$

$3)$ On the basis of the following observation made with aqueous solutions, assign secondary valences to metal in the following compounds:

$\begin{matrix} Formula & Moles of A g C l precipitated per mole of the compounds with excess A g N O_{3} P t C l_{4} .2 H C l & 0 \end{matrix}$

$4)$ On the basis of the following observation made with aqueous solutions, assign secondary valences to metal in the following compounds:

$\begin{matrix} Formula & Moles of A g C l precipitated per mole of the compounds with excess A g N O_{3} C o C l_{3} & 1 \end{matrix}$

$5)$ On the basis of the following observation made with aqueous solutions, assign secondary valences to metal in the following compounds:

$\begin{matrix} Formula & Moles of A g C l precipitated per mole of the compounds with excess A g N O_{3} P t C l_{2} .2 N H_{3} & 0 \end{matrix}$

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Solution

$1)$ Identification of real structural formula of the compound

Since, the given compound gives two moles of $A g C l$ on reaction with excess $A g N O_{3} .$

So, possible structural formula of the compound is: $[P d (N H_{3})_{4}] C l_{2}$

The reaction involved, follows as:

$[P d (N H_{3})_{4}] C l_{2} Excess of A g N O_{3} - --------- \to [P d (N H_{3})_{4}]^{2 +} + 2 A g C l (↓)$

Secondary valences

The secondary valences are the number of ions or molecules that are coordinated to the metal ion. It is the number of donor atom of ligands attached/coordinated to metal ion.

Hence, the secondary valences of the metal in the given formula are $4$ which is satisfied by $4 N H_{3}$ ligand.

$2)$ Identification of real structural formula of the compound

Since, the given compound gives two moles of $A g C l$ on the reaction with excess $A g N O_{3} .$

So,possible structual formula of the compound is:
$[N i (H_{2} O)_{6}] C l_{2}$

The reaction involved, follows as:

$[N i (H_{2} O)_{6}] C l_{2} Excess of A g N O_{3} - --------- \to [N i (H_{2} O)_{6}]^{2 +} + 2 A g C l (↓)$

Secondary valences

The secondary valences are the number of ions or molecules that are coordinated to the metal ion. It is the number of donor atom of ligands attached/coordinated to metal ion.

Hence, the secondary valences of the metal in the given formula are $6$ which is satisfied by $6 H_{2} O$ ligands.

$3)$ Identification of real structural formula of the compound

Since, the given compound gives zero moles of $A g C l$ on reaction with excess $A g N O_{3} .$

So,possible structual formula of the compound is:
$H_{2} [P t C l_{6}]$

The reaction involved, follows as:

$H_{2} [P t C l_{6}] \to [P t C l_{6}]^{2 -} + 2 H^{+}$

$[P t C l_{6}]^{2 -} Excess of A g N O_{3} - --------- \to No reaction$

Secondary valences

The secondary valences are the number of ions or molecules that are coordinated to the metal ion. It is the number of donor atom of ligands attached/coordinated to metal ion.

Hence, the secondary valences of the metal in the given formula are $6$ which is satisfied by $6 C l^{-}$ ligands.

$4)$ Identification of real structural formula of the compound

Since, the given compound gives one moles of $A g C l$ on the reaction with excess $A g N O_{3} .$

So,possible structual formula of the compound is:
$[C o (N H_{3})_{4} C l_{2}] C l$

The reaction involved, follows as:

$[C o (N H_{3})_{4} C l_{2}] C l Excess of A g N O_{3} - --------- \to [C o (N H_{3})_{4} C l_{2}]^{+} + A g C l (↓)$

Secondary valences

The secondary valences are the number of ions or molecules that are coordinated to the metal ion. It is the number of donor atom of ligands attached/coordinated to metal ion.

Hence, the secondary valences of the metal in the given formula are $6$ which is satisfied by $2 C l^{-}$ ligands.

$5)$ Identification of real structural formula of the compound

Since, the given compound gives zero moles of $A g C l$ on the reaction with excess $A g N O_{3} .$

So,possible structual formula of the compound is:
$[P t (N H_{3})_{2} C l_{2}]$

The reaction involved, follows as:

$[P t (N H_{3})_{2} C l_{2}] Excess of A g N O_{3} - --------- \to N o r e a c t i o n$

Secondary valences

The secondary valences are the number of ions or molecules that are coordinated to the metal ion. It is the number of donor atom of ligands attached/coordinated to metal ion.

Hence, the secondary valences of the metal in the given formula are $4$ which is satisfied by $2 N H_{3}$ ligands.

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Similar questions

Some properties are listed in the following Table. Distinguish between metals and non-metals on the basis of these properties.

Properties

Metals

Non-metals

1. Appearance

2. Hardness

3. Malleability

4. Ductility

5. Heat Conduction

6. Conduction of Electricity

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⁵

⁶

⁷

⁸

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Formula	Moles of $A g C l$ precipitated per mole of the compounds with excess $A g N O_{3}$
(i) $P d C l_{2} .4 N H_{3}$	$2$
(ii) $N i C l_{2} .6 H_{2} O$	$2$
(iii) $P t C l_{4} .2 H C l$	$0$
(iv) $C o C l_{3} .4 N H_{3}$	$1$
(v) $P t C l_{2} .2 N H_{3}$	$0$

(i) P d C l_{2} .4 N H_{3}

(i i) N i C l_{2} .6 H_{2} O

(i i i) P t C l_{4} .2 H C l

(i v) C o C l_{3} .4 N H_{3}

(v) P t C l_{2} .2 N H_{3}

C o C l_{3} .4 N H_{3}

A g N O_{3}

A g C l

C o C l_{3} .4 N H_{3}

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