Question

1) On the Pauling's electronegativity scale,which element is next to F.
2) Why ${Ca}^{2+}$ has smaller ionic radius than $K^{+}$?

Answer 1

(1)Generally atomic Radius decreases

Ionisation energy Incomes and then

electronegativity Incomes.

on Pauling's electronegativity

scale $O_2$ (oxygen) is next to F

$F\to 3.98$

$O\to 3.44$ EN

(2) In $C{a}^{2+}$. the number of profanes in

the numbers of the ions is Increasing

That tend to pull the electrons

more and more towards the center

of ion $\to$ causing ionic radii to fall

as compared to $K^{⨁}$

$k^{+}>C{a}^{2+}$: fonic Radii