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Osmotic Pressure and Osmotic Potential

1. Pcl5=pcl3+...

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1. Pcl5=pcl3+cl2 Vapour density is found to be hundred when 1 mole of pcl5 is taken in 10dm3 flask at 300k. Thus, equilibrium pressure is :- 1. 1.00 atm 2. 4.92 atm 3. 2.46 atm 4. 2.57 atm

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Q. In an evacuated closed isolated chamber at

250^{o} C

.02

P {C l}_{5}

.01

{C l}_{2}

(P {C l}_{5} ⇌ P {C l}_{3} + {C l}_{2})

. At equilibrium density of mixture was

2.49 g / L

and pressure was

1

atm. The number of total moles at equilibrium will be approximately:

Q. In the reaction,

P C l_{5} ⇌ P C l_{3} + C l_{2}

, the amount of

P C l_{5}, P C l_{3}

P C l_{2}

at equilibrium are

2

moles each and the total pressure is

3

atm. The equilibrium constant

K_{p}

a

P {C l}_{5}

undergoes thermal dissociation as

P {C l}_{5} ⇌ P {C l}_{3} + C l_{2}

; the mole fraction

P {C l}_{3}

at equilibrium is 0.25 and the total pressure is 2 atm. The partial pressure is

{C l}_{2}

at equilibrium is:

Q. A reaction at equilibrium involving 2 moles each of

P C l_{5}, P C l_{3},

C l_{2}

is maintained at

250^{o} C

and a total pressure of 3 atm. The value of

K_{p}

P C l_{5} ⇌ P C l_{3} + C l_{2}

Q. 2 mole each of

P C l_{5}

C l_{2}

P C l_{3}

are taken in 5lt. flask at

27^{o} C

. After following equilibrium is attained in gaseous phase,

P C l_{5} ⇌ P C l_{3} + C l_{2}, P C l_{5}

is found to be 40% dissociated. Calculate equilibrium constant

K_{c}

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