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Positional Isomerism

1-Pentyne and...

Question

1-Pentyne and 2-Pentyne can be distinguished by:

Silver mirror test

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Iodoform test

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Baeyers test

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Addition reaction of

H_{2}

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Solution

The correct option is B Silver mirror test
1-Pentyne is the terminal alkyne which gives grey/silver coloured precipitate of silver alkynide with ammonical silver nitrate solution.
Where as 2-Pentyne does not react with this solution

$C H_{3} C H_{2} C H_{2} C \equiv C H + A g N O_{3} + N H_{4} O H ⟶ C H_{3} C H_{2} C H_{2} C \equiv C A g ↓ N H_{4} N O_{3} + H_{2} O$

Suggest Corrections

Similar questions

O_{3} / H_{2} O

(A)

4 N

K O H

175

(A)

(B)

(C)

175

Δ G

B ⇌ A

Δ G_{1} = ?

B ⇌ C

Δ G_{2} = ?

Δ G_{1}

Δ G_{2}

A, B

C

A, B

C

\to 1 -

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