Question

1.Sam has 7 chocolates more than two times the chocolates Ben has. If Sam has 47 chocolates ,how many chocolates does Ben have ?
2.Find the diagonal of a rectangle whose length is 12cm and width is 9cm .
3.Simplify:[−845÷249]–[−45]

Answer 1

Dear Student,

$$\begin{gathered} 1.LetthenumberofchocolatesBenhasbexandnumberofchocolatesSamhasbe2x+7 \\ Thenaccordingtothequestion, \\ 2x+7=47 \\ 2x=40 \\ x=20 \\ Benhas20chocolates \\ 2.U\sin gPythagorasTheorem, \\ {\left(Diagonal\right)}^2={12}^2+9^2=225Lengthofdiagonal=15cm \\ 3.\frac{-845}{249}-(-45)=-3.39+45=41.61 \end{gathered}$$


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