The correct option is C 0(1+secθ) (1 secθ) +tan^2θ =1 sec^2θ +tan^2θ = tan^2 θ+tan^2 θ [∵1 sec^2θ= tan^2 θ] = 0. ...

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Trigonometric Identities

1+θ1-θ+tan 2θ...

Question

$(1 + s e c θ) (1 - s e c θ) + t a n^{2} θ =$

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Solution

$(1 + s e c θ) (1 - s e c θ) + t a n^{2} θ$
$= 1 - s e c^{2} θ + t a n^{2} θ$
$= - t a n^{2} θ + t a n^{2} θ [∵ 1 - s e c^{2} θ = - t a n^{2} θ]$
= $0$ .

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